Use Inventory only Once

[metalmario991]

I am creating a puzzle where you have to use an item on a tree in order to get something. I have it set up with the whole active inventory thing but what do I do to make it so you can do it only once. I know it has something to do with Game.DoOnlyOnce but I'm not sure what I should put in the (). If I put cTree2_UseInv() wouldn't it make it so I couldn't do anything else with the tree? I'm a little confused here.

[xil]

cTree2_UseInv() I believe is the correct approach.

When you say:

If I put cTree2_UseInv() wouldn't it make it so I couldn't do anything else with the tree?

This makes me a little confused if I'm honest. If you had a function:

Code: ags

function cTree2_UseInv()
{
  if(player.ActiveInventory == iMyInvItem)
  {
    // do stuff here
  }
}

This would allow you to do other things to the tree as well, so the answer to your question (in a way) is no.

You might have meant something else, so just in case, here are some things you can do:

-----

Remove the item after use to stop a player using the item on the tree multiple times:

Code: ags

function cTree2_UseInv()
{
  if(player.ActiveInventory == iMyInvItem)
  {
    // do stuff
    player.LoseInventory(iMyInvItem);
  }
}

-----

Perhaps you meant using more than one item?

Code: ags

function cTree2_UseInv()
{
  if(player.ActiveInventory == iMyInvItem)
  {
    // do stuff
  }
  
  if(player.ActiveInventory == iMyOtherInvItem)
  {
    // do other stuff for other item
  }
}

-----

Perhaps you mean you could do other interactions?

Well for that you would simply add more events like cTree2_Look etc via the character properties window.

I hope that helps!

[HandsFree]

You just have to put a unique string in there.
if (Game.DoOnceOnly("use thing on tree"))

If it's only a specific item you should use only once, it would be something like:

Code: ags

cTree2_UseInv() {
  if (player.ActiveInventory == iAxe){
    if (Game.DoOnceOnly("use axe on tree")) CutDownTree;
    else player.Say("I already did that");
  }
  else  etc.
}